Ответы на вопрос:
Log(2)(x-1)-log(2)(x+1)-log(x+1/x-1)(2)> 0 одз x-1> 0⇒ x> 1 u x+1> 0⇒ x> -1 u x-1≠1 x≠1⇒x> 1⇒x∈(1; ∞)log(-1)/(x+1)) + 1/log(+1)/(x-1))> 0 (x+1)/(x-1)=tlog(2)1/t +1/log(2)t> 0 (2)t)²+1)/log(2)t> 0 log(2)t=a (1-a)(1+a)/a> 0 a=1 a=-1 a=0 + _ + _ -1 0 1 1)a< -1⇒log(2)t< -1⇒t< 1/2 (x+1)/(x-1)< 1/2(2x+2-x+1)/(x-1)< 0(x+3)/(x-1)< 0x=-3 x=1 + _ + -3 1-3< x< 1 u x> 1⇒ нет решения2)0< a< 1⇒0< log(2)t< 1a)log(2)t> 0t> 1⇒ (x+1)/(x-1)> 1(x+1-x+1)/(x-1)> 02/(x-1)> 0x-1> 0x> 1b) log(2)t< 1t< 2⇒(x+1)/(x-1)< 2(x+1-2x+2)/(x-1)< 0(3-x)/(x-1)< 0x=3 x=1 _ + _ 1 3x< 1 u x> 3 u x> 1⇒x∈(3; ∞)
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