Ответы на вопрос:
b^5÷b^2=b^(5-2)=b^3
y^11÷y^7=y^(11-7)=y^4
a^7÷a^7=a^(7-7)=a^0=1
b^9÷b^9=b^(9-9)=b^0=1
Tg5x * sin10x + cos10x - cos20x = 0 sin5x / cos5x * (2sin5x * cos5x) + cos10x - cos20x = 0 2sin^2 5x + cos^2 5x - sin^2 5x - cos2 0x = 0 cos^2 5x + sin^2 5x - cos20x = 0 1 - cos20x = 0 cos20x = 1 20x = 360град * n x = 18град * n
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