Ответы на вопрос:
n(h2so4) = 100g * 0,098 / 98g/mol = 0.1 mol
h2so4 + ba(oh)2 = baso4 + 2h2o
==> n(h2so4) = n(ba(oh)2)
==> n(ba(oh)2) = 0,1mol
m(solution) = 0,1 mol * (137 + 32 + 2)g / 0,05 = 342g
m(h2o)1 = 100 - 100*0,098 = 90,2 g
m(h2o)2 = 342 - 342*0,05 = 324,9 g
m(h2o)3 = 0,1 mol * 2 * 18 = 3,6 g
===> sum m(h2o) = 90,2 g + 324,9g + 3,6g = 418,7 g
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