X^2+5x(дробная черта) 1-6x + 41x^2-2x(дробная черта) 6x-1 , , в 0 ( полное решение без решебника! )
196
362
Ответы на вопрос:
Solve for x over the real numbers: -(x (x-5))/((6 x-1) (41 x^2-8 x+1)) = 0 multiply both sides by -1: (x (x-5))/((6 x-1) (41 x^2-8 x+1)) = 0 multiply both sides by (6 x-1) (41 x^2-8 x+1): x (x-5) = 0 split into two equations: x-5 = 0 or x = 0 add 5 to both sides: answer: x = 5 or x = 0
Популярно: Алгебра
-
Komarova2417.07.2020 19:55
-
fdhhivanova0004.06.2020 09:03
-
oleksandrskorbat13.10.2020 15:29
-
умняшка22003.06.2021 01:43
-
kazz1m24.06.2021 23:27
-
naval201805.02.2022 11:56
-
Blackmamba0609.12.2022 03:14
-
slava3101216.02.2020 02:12
-
baller5925.03.2023 18:57
-
mariapopova7728.08.2020 03:48