Ответы на вопрос:
=3р(1+0.2p+0.01p^2)-0.6p^2= =3p+0.6p^2+0.03p^3-0.6p^2= =3p+0.03p^3= 3*(-2)+0.03 (-2)^3= -6+0.03*(-8)= =-6-0.24=-6.24
1)17cos2α=17(1-2sin²α)=|sinα=0.8|=17(1-2×0.64)=6.12 2)49cos2α=49(2cos²α-1)=|cosα=2/7|=49(2×4/49-1)=-41 3)30√3sin1020°=√3sin(360°×3-60°)=√3sin(-60°)=-√3×√3/2=-3/2 4)-34√3cos930°=-34√3cos(360°×2+180°+30°)= -34√3(-cos30°)=34×√3×√3/2=3×17=51
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