Ответы на вопрос:
Сos 2x + cos 4x + cos 6x = 0 2 cos 4x cos 2x + cos 4x = 0 cos 4x ( 2cos 2x + 1) = 0 cos 4x = 0 или 2cos 2x +1 = 0 4x = π/2 + πk,k∈z 2cos 2x = -1 x = π/8 + πk/4, k∈z cos 2x = -1/2 2x = +-arccos(-1/2) + 2πn , n∈z 2x = +-2π/3 + 2πn, n∈z x = +- π/3 + π n, n ∈z
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