Ответы на вопрос:
Sin(2π/3)cos(π/3) + cos(π/3)sin(π/3) = 2sin(π/3)cos(π/3)cos(π/3) + + sin(π/3)cos(π/3) = sin(π/3)cos(π/3) * [2cos(π/3) + 1] = = (√3/2)*(1/2)* [ 2*(1/2) + 1] = (√3/4) * 2 = √3/2
Популярно: Алгебра
-
lana03093528.03.2020 20:29
-
P0SEYD0N21.02.2023 20:03
-
kirilln212.02.2022 02:30
-
Veid18.12.2020 05:40
-
Викa100000011.06.2022 05:32
-
kirill13125a29.12.2021 02:11
-
Бацио23.03.2023 18:31
-
oksana141018.07.2021 03:58
-
ychenicaa722.06.2020 07:21
-
ChrisUnte05.04.2020 01:18