Решить. *> = больше либо равно sinx> =корень2/2 sinx> =1/2 sinx< -(корень3/2) sinx< -(корень2/2)
179
252
Ответы на вопрос:
1) sinx ≥ √2/2 arcsin(√2/2) + 2πn ≤ x ≤ π - arcsin(√2/2) + 2πn, n∈z π/4 + 2πn ≤ x ≤ π - π/4 + 2πn, n∈z π/4 + 2πn ≤ x ≤ 3π/4 + 2πn, n∈z 2) sinx ≥ 1/2 arcsin(1/2) + 2πn ≤ x ≤ π - arcsin(1/2) + 2πn, n∈z π/3 + 2πn ≤ x ≤ π - π/3 + 2πn, n∈z π/3 + 2πn ≤ x ≤ 2π/3 + 2πn, n∈z 3) sinx< - √3/2 - π - arcsin(- √3/2) + 2πn < x < arcsin(- √3/2) + 2πn, n∈z -π + π/3 + 2πn < x < - π/3 + 2πn, n∈z -2π/3 + 2πn < x < - π/3 + 2πn, n∈z 4) sinx < -(√2/2) - π - arcsin(- √2/2) + 2πn < x < arcsin(- √2/2) + 2πn, n∈z - π + π/4 + 2πn < x < - π/4 + 2πn, n∈z - 3π/4 + 2πn < x < - π/4 + 2πn, n∈z
Популярно: Алгебра
-
stasyaverh29.01.2023 02:04
-
вера73129.06.2020 06:06
-
polyaketoztt6723.08.2020 19:38
-
tinkimolko19.02.2023 03:22
-
45df4518.04.2023 06:10
-
Бла16124.02.2022 21:09
-
pogosanitka234526.03.2023 08:12
-
BeseliaslivMisfit24.01.2022 19:14
-
Sonta000418.10.2020 07:12
-
kveresgova27.06.2020 05:56