Ответы на вопрос:
x^2 + 3x + y^2 = 2 ( * ( - 1 )) - x ^2 - 3x - y^2 = - 2 x^2 + 3x - y^2 = - 6 - 2y^2 = - 8 y^2 = 4 y1 = + 2 y2 = ( - 2 ) 1) y = + 2 x^2 + 3x + y^2 = 2 x^2 + 3x + 4 = 2 x^2 + 3x + 2 = 0 d = 9 - 4*1*2 = 1 v d = 1 x1 = ( - 3 + 1 ) : 2 = ( - 1 ) x2 = ( - 2 ) 2) y = - 2 x^2 + 3x + y^2 = 2 x^2 + 3x + 4 = 2 x^2 + 3x + 2 = 0 x1 = ( - 1 ) x2 = ( - 2 ) ======================== ответ х = ( - 1 ) и ( - 2 ) y = 2 и ( - 2 )
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