Решите , нужно,31 1)y=ctgx свойства и график 2)\lim(x=> -3) 2x^2+x-15/3x^2+7x-6 3)0,2^x^2-2> 5 4)tg^2x-4tgx+3=0

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kostan555ua

Алгебра

4,4(50 оценок)

Решение: ^ - здесь степень v - корень квадр. д4.12 log 5 (7-x) = log 5 (3-x) + 1 log 5 (7-x) = log 5 (3-x) + log 5 (5) log 5 (7-x) = log 5 [5*(3-x)] 7-x = 5*(3-x) 7-x = 15 - 5x 5x = 8 x = 5/8 д4.11 log (x-5) 49 = 2 (x-5)^2 = 49 x^2 - 10x + 25 = 49 x^2 - 10x - 24 = 0 x(1) = 12 x(2) = - 2 д4.10 2^(3+x) = 0,4 * 5^(3+x) 2^3 * 2^x = 2/5 * 5^3 * 5^x 2^3 * 2^x = 2 * 5^2 * 5^x 2^x /5^x = 2/2^3 * 5^2 (2/5)^x = (5/2)^2 (2/5)^x = (2/5)^(-2) x = -2 д4.9 (1/3)^(3+x) = 9 [3^(-1)] ^(3+x) = 3^2 3^ (-3-x) = 3^2 -3-x = 2 x = -5 д4.6 v(6+5x) = x 6+5x = x^2 x^2 - 5x - 6 = 0 x(1) = +6 x(2) = -1 д4.5 v(1/(5-2x) = 1/3 1/(5-2x) = 1/9 5-2x = 9 2x = -4 x = -2 д4.4 11x / (2x^2 + 5) = 1 11x = 2x^2 + 5 2x^2 - 11x + 5 = 0 x(1) = +5 x(2) = +1/2 д4.3 x = (8x+25) / (x+8) x^2 + 8x = 8x + 25 x^2 = 25 x(1) = +5 x(2) = -5 д4.2 1/7 * x^2 = 9 1/7 1/7 * x^2 = 64/7 x^2 = 64 x(1) = +8 x(2) = -8 д4.1 (2x+7)^2 = (2x-1)^2 4x^2 + 28x + 49 = 4x^2 - 4x + 1 24x = - 48 x = -2

nastya2742

Алгебра

4,7(87 оценок)

F(x) = ∫ f(x) = ∫ (2x^2 + 3) dx = 2x^3/3 + 3x + c f( - 2) = - 5 2(-2)^3/3 - 6 + c = - 5 - 16/3 - 6 + c = - 5 - 16/3 + c = 1 c = 1 + 16/3 c = 19/3 f(x) = 2x^3/3 + 3x + 19/3