Ответы на вопрос:
1) 2cos(3x-п/3)=2 cos(3x - π/3) =1 3x - π/3 = 2πk, k∈z 3x = π/3 + 2πk, k∈z x = π/9 + 2πk/3, k∈z 2) cos (π/4 - x )= - 1 cos (x - π/4 ) = - 1 x - π/4 = π + 2πn, n∈z x = π + π/4 + 2πn, n∈z x = 5π/4 + 2πn, n∈z 3) 3cos (2x - π/6) = 0 cos (2x - π/6) = 0 2x = π/2 + π/6 + πm, m∈z 2x = 2π/3 + πm, m∈z x = π/3 + πm/2, m∈z
Х^2 - у^2 =72 х + у = 9метод подстановки: х=9-у; (9-y)^2-y^2=7281-18y+y^2-y^2=7281-18y=72-18y=-9y=0,5
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