Ответы на вопрос:
Сos2x=sin3x sin3x-cos2x=0 sin3x-sin(π/2-2x)=0 2sin(5x/2-π/4)cos(x/2+π/4)=0 sin(5x/2-π/4)=0⇒5x/2-π/4=πn⇒5x/2=π/4+πn⇒x=π/10+2πn/5 cos(x/2+π/4)=0⇒x/2+π/4=π/2+πn⇒x/2=π/4+πn⇒x=π/2+2πn x=π/10 u x=π/2
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