Ответы на вопрос:
(cos(2x+π/6)-√3/2)(cos(2x+π/6)+√3/2)sin(x/2)=0 1)cos(2x+π/6)=√3/2 2x+π/6=π/6+2πn u 2x+π/6=-π/6+2πn 2x=2πn u 2x=-π/3+2πn x=πn u x=-π/6+πn 2)cos(2x+π/6)=-√3/2 2x+π/6=5π/6+2πn u 2x+π/6=-5π/6+2πn 2x=2π/3+2πn u 2x=-π+2πn x=π/3+πn u x=-π/2+πn 3)sin(x/2)=0 x/2=πn x=2πn ответ x=+-π/3+πn, x=πn u x=-π/2+πn
Популярно: Алгебра
-
irinakotik201812.02.2023 01:28
-
denian1134310.12.2021 17:56
-
smirnovadashuta21.03.2023 05:17
-
kira26060628.09.2022 19:00
-
IAlisaI05.08.2022 16:59
-
moskalkov10.02.2020 01:38
-
daniil35827.03.2020 17:22
-
agroDan01.12.2022 22:56
-
12095494392102.09.2020 22:16
-
tatyanamasenko23.04.2021 15:24