Ответы на вопрос:
Sin(3x - π/4) = -√2/2 3x - π/4 = (-1)^n*arcsin(-√2/2) + πn, n∈z 3x - π/4 = (-1)^(n+1)*arcsin(√2/2) + πn, n∈z 3x - π/4 = (-1)^(n+1)*π/4) + πn, n∈z 3x = (-1)^(n+1)*(π/4) + π/4+ πn, n∈z x = (-1)^(n+1)*(π/12) + π/12+(πn)/3, n∈z
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