Ответы на вопрос:
7^[x+1] +3*7^[x] = 2^[x+5] + 3*2^[x] 7*7^[x] +3*7^[x] = 32*2^[x] + 3*2^[x] 10-32*(2/7)^[x] - 3*(2/7)^[x] = 0 10-35*(2/7)^[x]=0 3.5*(2/7)^[x] = 1 (2/7)^[x] = (2/7) x=1
7^ x * ( 7 + 3 ) = 2 ^ x * ( 2 ^ 5 + 3 ) 7 ^ x * 10 = 2 ^ x * 35 ( 7/2 ) ^ x = 35 / 10 3,5 ^ x = 3,5 x = 1
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