Ответы на вопрос:
ar(k2so4)=(39*2)+32+(16*4)=174
w(k2)= (2*39)/174(только это пиши дробью)=0,448*100=44,8
w(s)=(1*32)/174=0.183*100=18.3
w(o4)=(16*4)/174=0.367*100=36.7
ar(baco3)=137+13+(16*3)=198
w(ba)=(1*137)/198=0.691*100=69.1
w(c)=(1*13)/198=0.065*100=6.5
w(o3)=(3*16)/198=0.242*100=24.2
ar(agno3)=107+15+(16*3)=170
w(ag)=(1*107)/170=0.629*100=62.9
w(n)=(1*15)/170=0.088*100=8.8
w(03)=(3*16)/170=0.282*100=28.2
ar(cuno3)=64+15+(16*3)=127
w(cu)=(64*1)/127=0.503*100=50.3
w(n)=(1*15)/127=0.118*100=11.8
w(o3)=(16*3)/127=0.377*100=37.7
ar(fe2so4)=(55*2)+33+(16*4)=207
w(fe2)=(2*55)/207=0.531*100=53.1
w(s)=(1*3)/207=0.014*100=1.4
w(o4)=(16*4)/207=0.309*100=30.9
Популярно: Химия
-
вікуся4016.11.2022 12:01
-
муслима1822.01.2023 18:27
-
kryukova2002309.01.2021 17:34
-
shils20.04.2023 13:15
-
bartosz0403.08.2022 22:08
-
hychkairyna05.09.2021 11:45
-
msajkina01.10.2020 19:45
-
zobitkov03.08.2020 06:43
-
Leralove2005123.08.2020 03:58
-
Makc45721420.03.2023 05:13