Ответы на вопрос:
3-2y/2-y - 3y-2/2+y + 16y-y²-17/4-y² = 0 (3-2y)(2+-2)(2-y)/4-y² + 16y-y²-17/4-y² = 0 6+3y-4y-2y²-6y+3y²+4-2y+16y-y²-17/4-y² = 0 7y-7/4-y² = 0 2x-3/3 - 5x+1/4 = 4-x/28x-12-15x-3/12 - 4-x/2 = 0 -7x-5-24-6x/12 = 0 -13x-29/12
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