Ответы на вопрос:
max значение sin2x=1 ⇒ ymax =1.5+1=2.5 min sin2x=-1 ⇒ ymin=1.5·(-1)+1=-0.75+1=0.25
Y=1,5sin2x+1 e(y)∈1,5*[-1; 1]+1=[-1,5; 1,5]+1=[-0,5; 2,5] наим у=-0,5 наиб у=2,5
1) {3-x> 1 {x²-9≤9 3-x> 1 -x> 1-3 -x> -2 x< 2 x²-9≤9 x²-9-9≤0 x²-18≤0 (x-√18)(x+√18)≤0 (x-3√2)(x+3√2)≤0 x=3√2 x=-3√2 + - + -3√2 3√2 \\\\\\\\\\\\\\\\\\ -3√2 ≤ x ≤ 3√2 {x< 2 {-3√2 ≤ x ≤ 3√2 \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\ -3√2 2 3√2 \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\ -3√2 ≤ x < 2 x∈[-3√2; 2) 2. {x² ≥4 {x-3< 0 x² ≥4 x²-4≥0 (x-2)(x+2)≥0 x=2 x=-2 + - + -2 2 \\\\\\\\\\\\\\ \\\\\\\\\\\\\\\\\\\\\\ x≤-2 x≥2 x-3< 0 x< 3 {x≤ -2 {x≥ 2 {x< 3 \\\\\\\\\\\ \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\ -2 2 3 \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\ x∈(-∞; -2] u [2; 3) 3. {6x-x²> 0 {3-2x> x 6x-x²> 0 x²-6x< 0 x(x-6)< 0 x=0 x=6 + - + 0 6 \\\\\\\\\\\\\ 0< x< 6 3-2x> x -2x-x> -3 -3x> -3 x< 1 {0< x< 6 {x< 1 \\\\\\\\\\\\\\\\\\\\\\\\\\\\ 0 1 6 \\\\\\\\\\\\\\\\\\\\\\\\\\ 0< x< 1 x∈(0; 1)
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