Ответы на вопрос:
2x^2 + y^2 = 2xy + 4x 2x^2 + y^2 - 2xy = 4x (x - y)^2 = 4x - x^2 (x - y)^2 = x(4 -x) x - y = 0 4 - x = 0 y =4 x = 4 (x; y) = (4; 4) x - y = √ x(4 -x) x(4 -x) = x^2 4 - x = x 2x = 4 x=2 2* 2^2 + y^2 - 2* 2y = 4*2 8 + y^2 -4y = 8 y(y-4) = 0 y =4 (x; y) = (2; 4)
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