Преобразуйте заданное выражение в многочлен стандартного вида: 1) (3a²-4a+²+a-3) 2) (5x²+4x+3)+(3-2x-x²) 3) (3x³-2x²+7x-³+x²-4x+7) 4) (3,8x³-2,4x²+4,9x+3)+(-3,2x³+5,3x²-4x+5)
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Ответы на вопрос:
1) (3a²-4a+²+a-3)=3a²-4a+2-a²-a+3=2a²-5a+5 2) (5x²+4x+3)+(3-2x-x²)=5x²+4x+3+3-2x-x²=4x²-2x+6 3) (3x³-2x²+7x-³+x²-4x+7)=3x³-2x²+7x-3-x³-x²+4x-7=2x³-3x²+11x-10 4) (3,8x³-2,4x²+4,9x+3)+(-3,2x³+5,3x²-4x+5)= 3,8x³-2,4x²+4,9x+3-3,2x³+5,3x²-4x+5=0,6x³+2,9x²+0,9x+8
Sin(73π/24)*sin(37π/24)*sin(37π/12)=sin(3π+π/24)sin(π+13π/24)sin(3π+π/12)= -sinπ/24*(-sin13π/24)*(-sinπ/12)=-1/2(cos(13π/24-π/24)-cos(13π/24+π/24))* *sinπ/12=-1/2(cosπ/2-cos7π/12)*sinπ/12=1/2cos7π/12*sinπ/12= =1/4(sin(π/12-7π/12)+sin(π/12+7π/12))=1/4(sin(-π/2)+sin2π/3)= =1/4*(-1)+1/4*√3/2=-1/4+√3/8
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