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(корень из 5+корень из8)^2-корень из 90.

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Ответы на вопрос:


(  √5+  √8)^2-  √90.   √25+2√40+√72-√90= √167
amina327
4,6(43 оценок)

x\\x = (-\infty; 0) \cup [1] \cup [2; 3)" class="latex-formula" id="TexFormula2" src="https://tex.z-dn.net/?f=%28x%2B%5Cfrac%7B2%7D%7Bx%7D%29%28%5Cfrac%7B%7Cx-2%7C-1%7D%7B%5Csqrt%7B4-x%7D-1%7D%29%5E2%20-%203%28%5Cfrac%7B%7Cx-2%7C-1%7D%7B%5Csqrt%7B4-x%7D-1%7D%29%5E2%20%5Cgeq%200%5C%5C%28x%2B%5Cfrac%7B2%7D%7Bx%7D-3%29%28%5Cfrac%7B%7Cx-2%7C-1%7D%7B%5Csqrt%7B4-x%7D-1%7D%29%5E2%5Cgeq%200%5C%5C%5Cfrac%7Bx%5E2-3x%2B2%7D%7Bx%7D%20%28%5Cfrac%7B%7Cx-2%7C-1%7D%7B%5Csqrt%7B4-x%7D-1%7D%29%5E2%5Cgeq%200%5C%5C%5Cfrac%7B%28x-1%29%28x-2%29%28%7Cx-2%7C-1%29%5E2%7D%7Bx%28%5Csqrt%7B4-x%7D-1%29%5E2%7D%20%5Cgeq%200%5C%5C%5Cfrac%7B%28x-1%29%28x-2%29%28x-3%29%5E2%28x-1%29%5E2%7D%7Bx%284-x-1%29%7D%20%5Cgeq%200%5C%5C%5Cfrac%7B%28x-1%29%5E3%28x-2%29%28x-3%29%5E2%7D%7Bx%28x-3%29%7D%20%5Cleq%20%200%5C%5C---%280%29%2B%2B%2B%2B%2B%5B1%5D%2B%2B%2B%2B%2B%2B%5B2%5D-----%283%29%2B%2B%2B%2B%3Ex%5C%5Cx%20%3D%20%28-%5Cinfty%3B%200%29%20%5Ccup%20%5B1%5D%20%5Ccup%20%5B2%3B%203%29" title="(x+\frac{2}{x})(\frac{|x-2|-1}{\sqrt{4-x}-1})^2 - 3(\frac{|x-2|-1}{\sqrt{4-x}-1})^2 \geq 0\\(x+\frac{2}{x}-3)(\frac{|x-2|-1}{\sqrt{4-x}-1})^2\geq 0\\\frac{x^2-3x+2}{x} (\frac{|x-2|-1}{\sqrt{4-x}-1})^2\geq 0\\\frac{(x-1)(x-2)(|x-2|-1)^2}{x(\sqrt{4-x}-1)^2} \geq 0\\\frac{(x-1)(x-2)(x-3)^2(x-1)^2}{x(4-x-1)} \geq 0\\\frac{(x-1)^3(x-2)(x-3)^2}{x(x-3)} \leq 0\\---(0)+++++[1]++++++[2]-----(3)++++>x\\x = (-\infty; 0) \cup [1] \cup [2; 3)">

Объединяя с ОДЗ, получаем ответ.

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