Выражение 1) 2a(5a-7)-5a(3-2a); 2) (2b-3)(4b+9); 3) (2c-6)(8c++2)(5c-2);
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Ответы на вопрос:
1) 2a(5a-7)-5a(3-2a)=10а²-14а-15а+10а²=20а²-29а=а(20а-29)
2) (2b-3)(4b+9)= 8b²+6b-27
3) (2c-6)(8c++2)(5c-2)=16c²-38c-30- 25c²+4=-9с²-38с-26
1) 2a(5a-7)-5a(3-2a)=10а²-14а-15а+10а²=20а²-29а=а(20а-29)2) (2b-3)(4b+9)= 8b²+6b-273) (2c-6)(8c++2)(5c-2)=16c²-38c-30- 25c²+4=-9с²-38с-26
Possible derivation: d/dx(y) = d/dx(1/2 cos(2 x)-x) the derivative of y is zero: 0 = d/dx(-x+1/2 cos(2 x)) differentiate the sum term by term and factor out constants: 0 = (d/dx(cos(2 /2-d/dx(x) the derivative of x is 1: 0 = 1/2 (d/dx(cos(2 using the chain rule, d/dx(cos(2 x)) = ( dcos(u))/( du) ( du)/( dx), where u = 2 x and ( d)/( du)(cos(u)) = -sin(u): 0 = -1+1/2-d/dx(2 x) sin(2 x) factor out constants: 0 = -1-1/2 sin(2 x) 2 d/dx(x) simplify the expression: 0 = -1-(d/dx(x)) sin(2 x) the derivative of x is 1: answer: | | 0 = -1-1 sin(2 x)
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