Ответы на вопрос:
№3 mr(cuso4)=64+32+4*16= 160 w(cu)=64/160=0.4=40% w(s)=32/160=0.2=20% w(o4)=64/160=0.4=40% mr(fe2so3)=2*56++32+3*16=192 w(fe2)=112/192=0.58=58% w(s)=32/192=0.17=17% w(o3)=48/192=0.25=25% mr(hno3)=1+14+3*16=63 w(h)=1/63=0.02=2% w(n)=14/63=0.22=22% w(o3)=48/63=0.76=76%
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