Ответы на вопрос:
Cosα+2cos3α+cos5α=(cosα+cos5α)+2cos3α= =2cos((α+5α)/2)*cos((5α-α)/2)+2cos3α= =2cos3α*cos2α+2cos3α=2cos3α(cos2α+1)= =2cos3α(cos²α-sin²α+cos²α+sin²α)= =2cos3α*2cos²α=4cos3α*cos²α
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