Алгебра: Алгебра будь який один варіант ів

[tex]1)4x - {x}^{3} = 0 \ x imes (4 - {x}^{2} ) = 0 \ x = 0 \ 4 - {x}^{2} = 0 \ x = 0 \ x = - 2 \ x = 2 \ x1 = - 2 \ x2 = 0 \ x3 = 2[/tex][tex]3)4 {x}^{3} - 3 {x}^{2} = 4x - 3 \ {x}^{2} imes (4x - 3) = 4x - 3 \ {x}^{2} imes (4x - 3) - (4x - 3) = 0 \ (4x - 3) imes ( {x}^{2} - 1) = 0 \ 4x - 3 = 0 \ {x}^{2} - 1 = 0\ x1 = - 1 \ x2 = 0.75 \ x3 = 1[/tex][tex]2) - 20 {x}^{2} + 5 {x}^{4} = 0 \ - 5 {x}^{2} imes (4 - {x}^{2} ) = 0 \ {x}^{2} imes (4 - {x}^{2} ) = 0 \ {x}^{2}...

kburuncenco307

15.11.2021 04:04

Алгебра

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Алгебра будь який один варіант ів

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королева5720

Алгебра

4,4(14 оценок)

$1)4x - {x}^{3} = 0 \\ x \times (4 - {x}^{2} ) = 0 \\ x = 0 \\ 4 - {x}^{2} = 0 \\ x = 0 \\ x = - 2 \\ x = 2 \\ x1 = - 2 \\ x2 = 0 \\ x3 = 2$ $3)4 {x}^{3} - 3 {x}^{2} = 4x - 3 \\ {x}^{2} \times (4x - 3) = 4x - 3 \\ {x}^{2} \times (4x - 3) - (4x - 3) = 0 \\ (4x - 3) \times ( {x}^{2} - 1) = 0 \\ 4x - 3 = 0 \\ {x}^{2} - 1 = 0\\ x1 = - 1 \\ x2 = 0.75 \\ x3 = 1$ $2) - 20 {x}^{2} + 5 {x}^{4} = 0 \\ - 5 {x}^{2} \times (4 - {x}^{2} ) = 0 \\ {x}^{2} \times (4 - {x}^{2} ) = 0 \\ {x}^{2} = 0 \\ 4 - {x}^{2} = 0 \\ x1 = - 2 \\ x2 = 0 \\ x3 = 2$