Ответы на вопрос:
(x-1)(x-3)(x+5)(x+7)=297((x – 1)(x + – 3)(x + 7)) = 297; (x2 + 5x – x – 5)(x2 + 7x – 3x – 21) = 297; (x2 + 4x – 5)(x2 + 4x – 21) = 297.x2 + 4x = t, тогда : (t – 5)(t – 21) = 297.t2 – 21t – 5t + 105 = 297; t2 – 26t – 192 =0 t1=-6 и t2=32x2 + 4x = -6 или x2 + 4x = 32x2 + 4x + 6 = 0 x2 + 4x – 32 = 0d = 16 – 24 < 0 d = 16 + 128 > 0 нет корней x1 = -8; x2 = 4 ответ: x1=-8 , x2=4
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