Ответы на вопрос:
Sin2x + 2sin^2x = 0 2sinxcosx + 2sin^2x = 0 2sinx* ( cosx + sinx) = 0 2sinx = 0 sinx = 0 x = πk, k ∈ z sinx + cosx = 0 //: cosx ≠ 0 tgx + 1 = 0 tgx = - 1 x = arctg( - 1) + πk x = - π/4 + πk, k ∈ z
Популярно: Алгебра
-
454454545414.11.2022 22:03
-
liza139231.01.2021 00:43
-
TeT9l3uHa17.02.2021 00:05
-
zenalubimova16.01.2023 23:04
-
retul26.12.2020 07:02
-
elnur2211.10.2020 06:26
-
Tina210306.04.2023 10:31
-
abramchuk212.02.2023 06:53
-
Ilona00401.02.2020 05:03
-
GGGKazakhstan21.02.2022 03:03