Ответы на вопрос:
x mol 0.005 mol agno3+kcl = kno3+agcl↓ 1 mol 1 mol n(agcl) = m(agcl) / m(agcl) = 0.716 g / 143.5 g/mol = 0.005 mol x mol / 1 mol = 0.005 mol / 1 mol x = (0.005 mol * 1 mol) / 1 mol x = 0.005 mol, n(agno3) = 0.005 mol m(agno3) = n(agno3) * m(agno3) = 0.005 mol * 170 g/mol = 0.85 g m(agno3) = 0.85 g
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