Ответы на вопрос:
11/3*log(2/3)8-3log(2/3)3+log(2/3)6=log(2/3)∛8-log(2/3)3³+log(2/3)6= =log(2/3)2-log(2/3)27+log(2/3)6=log(2/3)(2*6/27)=log(2/3)(4/9)=2 2 log(1/7)(3x+4)=-1 {3x+4> 0⇒x> -4/3 {3x+4=7⇒3x=3⇒x=1 ответ х=1
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