Ответы на вопрос:
25 [0, 0, "a", 1] [1, 1, "b", 2] [1, 2, "bb", 3] [2, 2, "b", 4] [1, 3, "bbb", 5] [2, 3, "bb", 6] [3, 3, "b", 7] [1, 4, "bbbb", 8] [2, 4, "bbb", 9] [3, 4, "bb", 10] [4, 4, "b", 11] [1, 5, "bbbbb", 12] [2, 5, "bbbb", 13] [3, 5, "bbb", 14] [4, 5, "bb", 15] [5, 5, "b", 16] [0, 6, "abbbbba", 17] [6, 6, "a", 18] [6, 7, "aa", 19] [7, 7, "a", 20] [6, 8, "aaa", 21] [7, 8, "aa", 22] [8, 8, "a", 23] [5, 9, "baaab", 24] [9, 9, "b", 25] #ruby22 s = "abbbbbaaab" n = 0 for r in .size for l in 0..r t = s[l..r] if t.reverse == t n += 1 p [l,r,t,n] end end end
Популярно: Информатика
-
ніка6528.03.2023 06:55
-
helenkarchevskp08ll510.04.2020 06:59
-
курррва22820.03.2023 22:33
-
danilejik14.05.2020 07:21
-
i01n14.06.2021 21:33
-
АмелияРайс27.10.2022 07:54
-
Marinr06.03.2022 03:39
-
kenetic21323214.02.2022 13:30
-
roma1xayatov24.02.2022 01:56
-
sofyaoborina1216.11.2020 13:41