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kozinasofia2006
19.02.2021 06:50
Математика
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AOB = 90°. найдите AOC и ВОС​

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Zloo6024600
Zloo6024600
4,4(64 оценок)

а)

3x - 5 + x + 15 = 90 \\ 4x = 90 - 1 0\\ 4x = 80 \\ x = 20 \\\\ \angle AOC = 3 \times 20^{\circ} - 5^{\circ} = 55^{\circ} \\\angle \: BOC = 20^{\circ} + 15^{\circ} = 35^{\circ}

б)

4x + 30 + x = 90 \\ 5x = 90 - 30 \\ 5x = 60 \\ x = 12 \\ \\ \angle BOC = 4 \times 12^{\circ} + 30^{\circ} = 48^{\circ} + 30^{\circ} =78^{\circ} \\ \angle \: AOC = 12^{\circ}

в)

3x - 35 + 2x + 25 = 90 \\ 5x = 90 + 10 \\ 5x = 100 \\ x = 20 \\ \\ \angle AOC = 2 \times 20^{\circ} + 25 ^{\circ} = 65^{\circ} \\ \angle \: BOC= 3 \times 20^{\circ} - 35^{\circ} = 25^{\circ}

Соня12131415
Соня12131415
4,8(36 оценок)
2)5/8-(1/3+1/6)=5/+1)/6)=5/8-3/6=5/8-1/2=(5-4)/8=1/8; 4)16/21-(1/6+2/7)=16/+12)/42)=16/21-19/42=(32-19)/42=13/42; 6)7/8-(1/4+2/5)=7/+8)/20)=7/8-13/20=(14-13)/40=1/40.

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