Ответы на вопрос:
16a² + 24ac + 9c² + 12a + 9c = (16a² + 24ac + 9c²) + (12a + 9c) =
= [(4a)² + 2 * 4a * 3c + (3c)²] + 3(4a + 3c) = (4a + 3c)² + 3(4a + 3c) =
= (4a + 3c)(4a + 3c + 3)
1)(2x-3)(x+5)-2=11-(x-4)^22x^2-3x+10x-15=11-x^2+8x-16 2x^2-3x+10x-15-11+x^2-8x+16=03x^2-x-10=0 2)(5x-1)(5x+1)+20x^2=7x-3 25x^2-1+20x^2-7x+3=045x^2+-7x+2=0 3)(8-x)(8+x)+(1-4x)^2=12x^2+1 64-x^2+1-8x+16x^2-12x^2-1=0 13x^2-8x+64=0 16
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