Ответы на вопрос:
(x - 3)2 - 2x(x-2)(x+2) = (x-3)(2-x) ; 2x - 6 - 2x(x² + 2x - 2x - 4) = 2x - x² - 6 + 3x ; 2x - 6 - 2x(x² - 4) = - x² + 5x - 6 ; 2x - 6 - 2x³ + 8x = - x² +5x - 6 ; 2x - 2x³ + 8x + x² - 5x = - 6 +6 ; - 2x³ + x² + 5x = 0 | *(-1) ; 2x³ - x² - 5x = 0 ; x(2x² - x - 5) = 0; x₁ = 0 или 2x² - x - 5 = 0 d = b² - 4ac = (-1)² - 4*2*(-5) = 1 + 40 = 41 x₂ = (-b + √d) / 2*a = (1 + √41) / 4 < ==> x₃ = (-b - √d) / 2*a = (1 - √41) / 4 < ==> ответ: x₁ = 0 x₂ = x₃ =
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