(1+cosα+cos2α+cos3α)/(4cos α/2)
A) sinαcos2α;
B) cosαcos 3α/2;
C) cos2αsin 3α/2;
D) cos3αcos2α.
193
500
Популярно: Алгебра
-
bubink9323.03.2023 02:45
-
innocen25.09.2022 01:26
-
galaktionov96405.06.2022 01:43
-
JahKhalib22807.01.2021 03:58
-
AlinaAlina11062411.03.2023 03:35
-
sanya1897p08pyj31.01.2021 21:10
-
славик5503.12.2020 06:43
-
cat49720.03.2021 07:36
-
чо227.01.2023 19:54
-
Igrilla1999010.01.2023 04:24