Ответы на вопрос:
дано
m(CxHyNz) = 0.9 g
m(CO2) = 1.76 g
m(H2O) = 1.26 g
V(N2) = 0.224 L
D(возд) = 1.55
-------------------
CxHyNz - ?
M(CxHyNz) = 1.55 * 29 = 45 g/mol
n(C) = n(CO2) = m/M = 1.76 / 44 = 0.04 mol
n(H) = 2n(H2O) = 2n(m/M) = 2(1.26 / 18) = 0.14 mol
m(C) = 0.04 * 12 = 0.48 g
m(H) = n(H) * M(H) = 0.14 * 1 = 0.14 g
m(N) = m(CxHyNz) - (m(C) + m(H)) = 0.9 - (0.48 + 0.14) = 0.28 g
n(N) = m/M = 0.28 / 14 = 0.02 mol
n(C) : n(H) : n(N) = 0.04 : 0.14 : 0.02 = 2 : 7 : 1
C2H7N ==> C2H5NH2 - АМИНЭТИЛ
ответ C2H5NH2
Объяснение:
Популярно: Химия
-
тлрп27.04.2023 21:30
-
Mariya19781914.02.2023 10:05
-
Vika247105.01.2020 14:09
-
Potap4uk02.04.2023 09:23
-
FJFJKD9910.01.2022 09:34
-
AlexSubbotin1102.04.2023 07:44
-
saule1961122525.02.2020 19:45
-
Voight09.11.2020 18:03
-
alinapavlova31.08.2021 22:29
-
nacteylka07.02.2020 00:45