Составьте уравнения реакций,при которых можно осуществить следующие превращения: 1)сh4--> c2h5--> c6h6--> c6h5oh--> 2,4,6-трибромфенол; 2)ch4--> c2h6--> c3h8--> c6h14--> c6h6--> пикриновая кислота

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Kanesan

Химия

4,4(40 оценок)

2)ch4+cl2=ch3cl+hcl 1)2ch4=c2h2+3h2

ch3cl+2na+clch3=2nacl+ch3-ch3(c2h6) 3c2h2=c6h6

c2h6+cl2=c2h5cl+hcl c6h6+cl2=c6h5cl+hcl

c6h5cl+koh=c6h5oh+kcl

c2h5cl+2na+clch3=2nacl+c2h5-ch3(c3h8)

c3h8+cl2=c3h7cl+hcl c6h5oh+3br2=c6h2br3oh+3hbr

c3h7cl+2na clc3h7=2nacl+c3h7-c3h7(c6h14)

c6h14=c6h6+4h2

c6h6+cl2=c6h5cl+hcl

c6h5cl+koh=c6h5oh+kcl

c6h5oh+3ho-no2=c6h2(no2)3oh+3h2o

modamzubik

Химия

4,5(46 оценок)

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