Ответы на вопрос:
(ln(sin( x/ (x^4 -3x)) )'=1/ sin (x/(x^4 -3x)) * (sin(x/(x^4 -3x) )'= =1/sin(x/(x^4 -3x) ) * cos(x/(x^4 -3x) * (x/(x^4 -3x) )'= =(cos(x/(x^4 -3x) ) /sin(x/(x^4 -3x)) * (1*(x^4 -3x)-x(4x^3-3) )/(x^4 -3x)^2= =ctg (x/ (x^4 -3x) ) *(x^4 -3x -4x^4+3x) /(x^4 -3x)^2= =(-3x^4 *ctg(x/(x^4 -3x) ) ) /(x^4-3x)^2
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