Ответы на вопрос:
1-sin²(x/2-3π)-cos²(x/4)+sin²(x/4)=(1-sin²(x/2-3π²(x/4)-sin²(x/4))= =cos²(x/2-3π)-cos(2*(x/4))=(cos(3π-x/2))²-cos(x/2)=(-cos(x/2))²-cos(x/2)=cos²(x/2)-cos(x/2)
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