Ответы на вопрос:
1. х+2у=1 ху=-1 x+2y=1 x=-1\y -1\y+2y=1 -1+2y²-y=0 2y²-y-1=0 d=(-1)²-4*2*(-1)=9 y1=1-3\4=-2\4=-0,5 y2=1+4\4=1 x1=-1\-1\2=2 x2=-1\1=-1 (2 ; -0,5) (-1 ; 1) 2. х²+ху=6 х-у=4 х(х+у)=6 х=4+у (4+у)(4+у+у)=6 (4+у)(4+2у)=6 2y²+12y+10=0 2(y²+6y+5)=0 y²+6y+5=0 d=6²-4*5*1=36-20=16 y1=-6-4\2=-5 y2=-6+4\2=-1 x1=4+(-5)=-1 x2=4+(-1)=3 (-1; -5) (3; -1)
Популярно: Алгебра
-
Abbszbbs02.11.2021 06:05
-
alinanamcat1208.04.2023 03:11
-
POZZITIFFON3407.05.2022 00:27
-
dianavoronina454521.07.2020 08:37
-
annachernaya04ow7wxu25.10.2020 15:10
-
verachistova115.04.2020 17:49
-
semic124.06.2021 22:24
-
Gremlin22223.09.2020 01:46
-
LymarIvan01.10.2021 02:57
-
sofia20000002.10.2021 03:01