Ответы на вопрос:
Применяем способ группировки (4-t)³-t·(t-3)·(t+2)-64-t²+2t=(4-t)³-64 - t·(t-3)·(t+²-2t)= = (4-t)³-4³ - t·(t-3)·(t+²-2t)= (4-t-4)·((4-t)²+4(4-t)+16)- t·(t-3)·(t+2)-t·(t-2)= =-t·(16-8t+t²+16-4t+16)-t·(t-3)·(t+2)-t·(t-2)=t(t²-12t+48)-t·(t²-t-6)-t·(t-2)= =t·(t²-12t+48-t²+t+6-t+2)=t·(-12t+56)=-4t·(3t-14)
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