Ответы на вопрос:
Pascal: var x: integer; begin for x: = -10 to 10 do writeln('f(',x*0.2,') = ',x*x*x+12) end. f(-1.2) = -204 f(-1) = -113 f(-0.8) = -52 f(-0.6) = -15 f(-0.4) = 4 f(-0.2) = 11 f(0) = 12 f(0.2) = 13 f(0.4) = 20 f(0.6) = 39 f(0.8) = 76 f(1) = 137 f(1.2) = 228 f(1.4) = 355 f(1.6) = 524 f(1.8) = 741 f(2) = 1012
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