Ответы на вопрос:
Cos (π/6-a) + sin (π/6 +a) =cos (π/6-a) + cos(π/2 - π/6 -a)= =cos (π/6-a) + cos(π/3 -α) = 2сos(π/4-α) *cosπ/12= =2*√2/2(cosα + sinα)*sinπ/12= √2(cosα + sinα)*sinπ/12
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