Ответы на вопрос:
1) lim x-> -1 x^3+x^2-x-1/x^2+3x+2 = lim x-> -1 (x²-1)/(x+2) = 0/-1=0 (x²(x++1))/(x+1)(x+2)=((x²-1)(x+1))/(x+1)(x+2)=(x²-1)/(x+2) 2)lim x-> 1/3 6x^2-5x+1/27x^3-1 = lim x-> 1/3 (2x-1)/(9x²+3x+1) = (2*1/3-1)/(9*1/9 + 3*1/3+1)= (2/3-1)/(1+1+1)=-1/9 d=25-24=1x12=(5+-1)/12=1/2 1/3(3x-1)(2x-1)/(3x-1)(9x²+3x+1)=(2x-1)/(9x²+3x+1) 3)lim x-> 1,5 8x^3-36x^2+54x-27/4x^2-12x+9= limx-> 1.5 (2x-3)= 2*1.5-3=08x^3-36x^2+54x-27/4x^2-12x+9 = (2x-3)³/(2x-3)²=2x-3
Популярно: Алгебра
-
agaeva97402.04.2020 19:45
-
Borisovilya25.04.2022 21:23
-
alinakiseleva1225.04.2021 20:52
-
zarinayespulov11.02.2021 00:12
-
11lol2217.10.2021 05:59
-
Alla95008.11.2020 02:01
-
grgrgrgrgrrhrrhrgrgr20.01.2021 07:39
-
lazarenko226.05.2021 10:43
-
Tsenenks17.07.2022 05:59
-
макс1337200430.03.2020 13:19