Ответы на вопрос:
x²+2x×v2+15 = (v2+1)² + 2(v2+1) × v2 + 15 = 2+2v2+1 + 4+2v2+15 = 22 + 4v2.
Cos5x•cos3x•cosx = -sin5x•sin3x•cosx cos5x•cos3x•cosx + cosx•sin5x•sin3x = 0 cosx(cos5x•cos3x + sin5x•sin3x) = 0 cosx(cosx(5x - 3x)) = 0 cosx•cos2x = 0 cosx = 0 x = π/2 + πn, n ∈ z cos2x = 0 2x = π/2 + πn, n ∈ z x = π/4 + πn/2, n ∈ z.
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