Ответы на вопрос:
дано
m(ppa naoh) = 200 g
w(naoh) = 2%
m пр.(cu(oh)2) = 4 g
η(cu(oh)
m(naoh) = 200*2% / 100% = 4 g
2naoh+cuso4--> cu(oh)2+na2so4
m(naoh) = 40 g/mol
n(naoh) = m/m = 4/ 40 = 0.1 mol
2n(naoh) = n(cu(oh)2)
n(cu(oh)2) = 0.1 / 2= 0.05 mol
m(cu(oh)2) = 98 g/mol
m теор(cu(oh)2) = n*m = 0.05 * 98 = 4.9 g
η(cu(oh)2) =mпр.(cu(oh)2) /mтеор (cu(oh)2) *100% = 4/ 4.9 * 100%= 81.6%
ответ 81.6%
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