Ответы на вопрос:
mr(fe2o3) = 160
w(fe) = ar(fe) *n / mr(fe2o3) *100% = 56 *2 / 160 *100% = 70%
w(o) = ar(o) * n / mr(fe2o3) *100% = 16*3 / 160 *100% = 30%
mr(so2) = 32 + 16*2 = 64
w(s) = ar(s) *n / mr(so2) * 100% = 32 / 64 *100% = 50%
w(o) = ar(o) * n / mr(so2) *100% = 16 *2 / 64 *100% =50%
mr(caco3) = 100
w(ca) = ar(ca) * n / mr(caco3) * 100% = 40 / 100 * 100% = 40%
w(c) = ar(c) * n / mr(caco3) * 100% = 12 / 100 *100% = 12%
w(o) = ar(o) * n / mr(caco3) *100% = 16 *3 /100 *100% = 48%
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