Выручите
〖sin〗^2 x 〖cos〗^2 x+sinx cosx=0
2cosx cos4x+cosx-2cos4x-1=0
tg 3x/2 cos(π/6+x)=cos(π/6+x)
158
253
Ответы на вопрос:
A) 3x^2 - 12 = 0 /: 3 x^2 - 4 = 0 x^2 = 4 x = ± √4 x = ± 2 b) 3x - 4x^2 = 0 /: (-1) 4x^2 - 3x = 0 x (4x - 3) = 0 x = 0 ; 4x - 3 = 0 ==> 4x = 3 ==> x = 0,75 c) x^2 + 10x + 25 = 0 (x + 5)^2 = 0 x + 5 = 0 x = - 5
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