Ответы на вопрос:
Решение 2sinx*cosx = sinx - 2cosx + 1 sinx(2cosx - 1) + (2cosx - 1) = 0 (2cosx - 1)*(sinx + 1) = 0 1) 2cosx - 1 - 0 2cosx = 1 cosx = 1/2 x = (+ arccos(1/2) + 2πn, n ∈z x =( + -) (π/3) + 2πn, n∈z 2) sinx + 1 = 0 sinx = -1 x = - π/2 + 2πk, k∈z ответ: x =( + -) (π/3) + 2πn, n∈z; x = - π/2 + 2πk, k∈z
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