Ответы на вопрос:
Lg5=a; lg3=b; log30(8)=? log30(8)=lg8/lg30=3lg2/(lg5+lg2+lg3)= 3lg2/(a+b+lg2) lg2=? lg5=a; lg(5•2)/2=(lg5+lg2)/lg2=a lg5+lg2=alg2 lg5=lg2*(a-1) lg2=lg5/(a-1)=a/(a-1) lg2=a/(a-1) log30(8)=3lg2/(a+b+lg2)= 3a/(a-1)*1/(a+b+a/(a-1)) 3a/(a-1)*((a-1)/((a+b)(a-1)+a)= 3a/((a+b)(a-1)+a)= 3a/(a^2-a+ab-b+a)= 3a/(a^2+ab-b)
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