Ответы на вопрос:
Sin(x-3x)/cosxcos3x+sin2x/cos2x=sin2x/cos2x-sin2x/cosxcos3x=0 sin2x(cosxcos3x-cos2x)=0 cosx< > 0 cos2x< > 0 cos3x< > 0 x=пk 2cosxcos3x=2cos2x cos4x+cos2x=2cos2x cos4x-cos2x=0 -2sin3x*sinx=0 sin3x=0 x=пk/3
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